Integrand size = 24, antiderivative size = 124 \[ \int \frac {\left (d^2-e^2 x^2\right )^{7/2}}{d+e x} \, dx=\frac {5}{16} d^5 x \sqrt {d^2-e^2 x^2}+\frac {5}{24} d^3 x \left (d^2-e^2 x^2\right )^{3/2}+\frac {1}{6} d x \left (d^2-e^2 x^2\right )^{5/2}+\frac {\left (d^2-e^2 x^2\right )^{7/2}}{7 e}+\frac {5 d^7 \arctan \left (\frac {e x}{\sqrt {d^2-e^2 x^2}}\right )}{16 e} \]
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Time = 0.03 (sec) , antiderivative size = 124, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {679, 201, 223, 209} \[ \int \frac {\left (d^2-e^2 x^2\right )^{7/2}}{d+e x} \, dx=\frac {5 d^7 \arctan \left (\frac {e x}{\sqrt {d^2-e^2 x^2}}\right )}{16 e}+\frac {1}{6} d x \left (d^2-e^2 x^2\right )^{5/2}+\frac {\left (d^2-e^2 x^2\right )^{7/2}}{7 e}+\frac {5}{16} d^5 x \sqrt {d^2-e^2 x^2}+\frac {5}{24} d^3 x \left (d^2-e^2 x^2\right )^{3/2} \]
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Rule 201
Rule 209
Rule 223
Rule 679
Rubi steps \begin{align*} \text {integral}& = \frac {\left (d^2-e^2 x^2\right )^{7/2}}{7 e}+d \int \left (d^2-e^2 x^2\right )^{5/2} \, dx \\ & = \frac {1}{6} d x \left (d^2-e^2 x^2\right )^{5/2}+\frac {\left (d^2-e^2 x^2\right )^{7/2}}{7 e}+\frac {1}{6} \left (5 d^3\right ) \int \left (d^2-e^2 x^2\right )^{3/2} \, dx \\ & = \frac {5}{24} d^3 x \left (d^2-e^2 x^2\right )^{3/2}+\frac {1}{6} d x \left (d^2-e^2 x^2\right )^{5/2}+\frac {\left (d^2-e^2 x^2\right )^{7/2}}{7 e}+\frac {1}{8} \left (5 d^5\right ) \int \sqrt {d^2-e^2 x^2} \, dx \\ & = \frac {5}{16} d^5 x \sqrt {d^2-e^2 x^2}+\frac {5}{24} d^3 x \left (d^2-e^2 x^2\right )^{3/2}+\frac {1}{6} d x \left (d^2-e^2 x^2\right )^{5/2}+\frac {\left (d^2-e^2 x^2\right )^{7/2}}{7 e}+\frac {1}{16} \left (5 d^7\right ) \int \frac {1}{\sqrt {d^2-e^2 x^2}} \, dx \\ & = \frac {5}{16} d^5 x \sqrt {d^2-e^2 x^2}+\frac {5}{24} d^3 x \left (d^2-e^2 x^2\right )^{3/2}+\frac {1}{6} d x \left (d^2-e^2 x^2\right )^{5/2}+\frac {\left (d^2-e^2 x^2\right )^{7/2}}{7 e}+\frac {1}{16} \left (5 d^7\right ) \text {Subst}\left (\int \frac {1}{1+e^2 x^2} \, dx,x,\frac {x}{\sqrt {d^2-e^2 x^2}}\right ) \\ & = \frac {5}{16} d^5 x \sqrt {d^2-e^2 x^2}+\frac {5}{24} d^3 x \left (d^2-e^2 x^2\right )^{3/2}+\frac {1}{6} d x \left (d^2-e^2 x^2\right )^{5/2}+\frac {\left (d^2-e^2 x^2\right )^{7/2}}{7 e}+\frac {5 d^7 \tan ^{-1}\left (\frac {e x}{\sqrt {d^2-e^2 x^2}}\right )}{16 e} \\ \end{align*}
Time = 0.41 (sec) , antiderivative size = 133, normalized size of antiderivative = 1.07 \[ \int \frac {\left (d^2-e^2 x^2\right )^{7/2}}{d+e x} \, dx=\frac {\sqrt {d^2-e^2 x^2} \left (48 d^6+231 d^5 e x-144 d^4 e^2 x^2-182 d^3 e^3 x^3+144 d^2 e^4 x^4+56 d e^5 x^5-48 e^6 x^6\right )}{336 e}-\frac {5 d^7 \log \left (-\sqrt {-e^2} x+\sqrt {d^2-e^2 x^2}\right )}{16 \sqrt {-e^2}} \]
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Time = 2.23 (sec) , antiderivative size = 116, normalized size of antiderivative = 0.94
method | result | size |
risch | \(\frac {\left (-48 e^{6} x^{6}+56 d \,e^{5} x^{5}+144 d^{2} e^{4} x^{4}-182 x^{3} d^{3} e^{3}-144 d^{4} e^{2} x^{2}+231 d^{5} e x +48 d^{6}\right ) \sqrt {-x^{2} e^{2}+d^{2}}}{336 e}+\frac {5 d^{7} \arctan \left (\frac {\sqrt {e^{2}}\, x}{\sqrt {-x^{2} e^{2}+d^{2}}}\right )}{16 \sqrt {e^{2}}}\) | \(116\) |
default | \(\frac {\frac {\left (-e^{2} \left (x +\frac {d}{e}\right )^{2}+2 d e \left (x +\frac {d}{e}\right )\right )^{\frac {7}{2}}}{7}+d e \left (-\frac {\left (-2 e^{2} \left (x +\frac {d}{e}\right )+2 d e \right ) \left (-e^{2} \left (x +\frac {d}{e}\right )^{2}+2 d e \left (x +\frac {d}{e}\right )\right )^{\frac {5}{2}}}{12 e^{2}}+\frac {5 d^{2} \left (-\frac {\left (-2 e^{2} \left (x +\frac {d}{e}\right )+2 d e \right ) \left (-e^{2} \left (x +\frac {d}{e}\right )^{2}+2 d e \left (x +\frac {d}{e}\right )\right )^{\frac {3}{2}}}{8 e^{2}}+\frac {3 d^{2} \left (-\frac {\left (-2 e^{2} \left (x +\frac {d}{e}\right )+2 d e \right ) \sqrt {-e^{2} \left (x +\frac {d}{e}\right )^{2}+2 d e \left (x +\frac {d}{e}\right )}}{4 e^{2}}+\frac {d^{2} \arctan \left (\frac {\sqrt {e^{2}}\, x}{\sqrt {-e^{2} \left (x +\frac {d}{e}\right )^{2}+2 d e \left (x +\frac {d}{e}\right )}}\right )}{2 \sqrt {e^{2}}}\right )}{4}\right )}{6}\right )}{e}\) | \(248\) |
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Time = 0.38 (sec) , antiderivative size = 116, normalized size of antiderivative = 0.94 \[ \int \frac {\left (d^2-e^2 x^2\right )^{7/2}}{d+e x} \, dx=-\frac {210 \, d^{7} \arctan \left (-\frac {d - \sqrt {-e^{2} x^{2} + d^{2}}}{e x}\right ) + {\left (48 \, e^{6} x^{6} - 56 \, d e^{5} x^{5} - 144 \, d^{2} e^{4} x^{4} + 182 \, d^{3} e^{3} x^{3} + 144 \, d^{4} e^{2} x^{2} - 231 \, d^{5} e x - 48 \, d^{6}\right )} \sqrt {-e^{2} x^{2} + d^{2}}}{336 \, e} \]
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Time = 1.61 (sec) , antiderivative size = 520, normalized size of antiderivative = 4.19 \[ \int \frac {\left (d^2-e^2 x^2\right )^{7/2}}{d+e x} \, dx=d^{5} \left (\begin {cases} \frac {d^{2} \left (\begin {cases} \frac {\log {\left (- 2 e^{2} x + 2 \sqrt {- e^{2}} \sqrt {d^{2} - e^{2} x^{2}} \right )}}{\sqrt {- e^{2}}} & \text {for}\: d^{2} \neq 0 \\\frac {x \log {\left (x \right )}}{\sqrt {- e^{2} x^{2}}} & \text {otherwise} \end {cases}\right )}{2} + \frac {x \sqrt {d^{2} - e^{2} x^{2}}}{2} & \text {for}\: e^{2} \neq 0 \\x \sqrt {d^{2}} & \text {otherwise} \end {cases}\right ) - d^{4} e \left (\begin {cases} \sqrt {d^{2} - e^{2} x^{2}} \left (- \frac {d^{2}}{3 e^{2}} + \frac {x^{2}}{3}\right ) & \text {for}\: e^{2} \neq 0 \\\frac {x^{2} \sqrt {d^{2}}}{2} & \text {otherwise} \end {cases}\right ) - 2 d^{3} e^{2} \left (\begin {cases} \frac {d^{4} \left (\begin {cases} \frac {\log {\left (- 2 e^{2} x + 2 \sqrt {- e^{2}} \sqrt {d^{2} - e^{2} x^{2}} \right )}}{\sqrt {- e^{2}}} & \text {for}\: d^{2} \neq 0 \\\frac {x \log {\left (x \right )}}{\sqrt {- e^{2} x^{2}}} & \text {otherwise} \end {cases}\right )}{8 e^{2}} + \sqrt {d^{2} - e^{2} x^{2}} \left (- \frac {d^{2} x}{8 e^{2}} + \frac {x^{3}}{4}\right ) & \text {for}\: e^{2} \neq 0 \\\frac {x^{3} \sqrt {d^{2}}}{3} & \text {otherwise} \end {cases}\right ) + 2 d^{2} e^{3} \left (\begin {cases} \sqrt {d^{2} - e^{2} x^{2}} \left (- \frac {2 d^{4}}{15 e^{4}} - \frac {d^{2} x^{2}}{15 e^{2}} + \frac {x^{4}}{5}\right ) & \text {for}\: e^{2} \neq 0 \\\frac {x^{4} \sqrt {d^{2}}}{4} & \text {otherwise} \end {cases}\right ) + d e^{4} \left (\begin {cases} \frac {d^{6} \left (\begin {cases} \frac {\log {\left (- 2 e^{2} x + 2 \sqrt {- e^{2}} \sqrt {d^{2} - e^{2} x^{2}} \right )}}{\sqrt {- e^{2}}} & \text {for}\: d^{2} \neq 0 \\\frac {x \log {\left (x \right )}}{\sqrt {- e^{2} x^{2}}} & \text {otherwise} \end {cases}\right )}{16 e^{4}} + \sqrt {d^{2} - e^{2} x^{2}} \left (- \frac {d^{4} x}{16 e^{4}} - \frac {d^{2} x^{3}}{24 e^{2}} + \frac {x^{5}}{6}\right ) & \text {for}\: e^{2} \neq 0 \\\frac {x^{5} \sqrt {d^{2}}}{5} & \text {otherwise} \end {cases}\right ) - e^{5} \left (\begin {cases} \sqrt {d^{2} - e^{2} x^{2}} \left (- \frac {8 d^{6}}{105 e^{6}} - \frac {4 d^{4} x^{2}}{105 e^{4}} - \frac {d^{2} x^{4}}{35 e^{2}} + \frac {x^{6}}{7}\right ) & \text {for}\: e^{2} \neq 0 \\\frac {x^{6} \sqrt {d^{2}}}{6} & \text {otherwise} \end {cases}\right ) \]
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Result contains complex when optimal does not.
Time = 0.28 (sec) , antiderivative size = 129, normalized size of antiderivative = 1.04 \[ \int \frac {\left (d^2-e^2 x^2\right )^{7/2}}{d+e x} \, dx=-\frac {5 i \, d^{7} \arcsin \left (\frac {e x}{d} + 2\right )}{16 \, e} + \frac {5}{16} \, \sqrt {e^{2} x^{2} + 4 \, d e x + 3 \, d^{2}} d^{5} x + \frac {5 \, \sqrt {e^{2} x^{2} + 4 \, d e x + 3 \, d^{2}} d^{6}}{8 \, e} + \frac {5}{24} \, {\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {3}{2}} d^{3} x + \frac {1}{6} \, {\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {5}{2}} d x + \frac {{\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {7}{2}}}{7 \, e} \]
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Time = 0.29 (sec) , antiderivative size = 103, normalized size of antiderivative = 0.83 \[ \int \frac {\left (d^2-e^2 x^2\right )^{7/2}}{d+e x} \, dx=\frac {5 \, d^{7} \arcsin \left (\frac {e x}{d}\right ) \mathrm {sgn}\left (d\right ) \mathrm {sgn}\left (e\right )}{16 \, {\left | e \right |}} + \frac {1}{336} \, {\left (\frac {48 \, d^{6}}{e} + {\left (231 \, d^{5} - 2 \, {\left (72 \, d^{4} e + {\left (91 \, d^{3} e^{2} - 4 \, {\left (18 \, d^{2} e^{3} - {\left (6 \, e^{5} x - 7 \, d e^{4}\right )} x\right )} x\right )} x\right )} x\right )} x\right )} \sqrt {-e^{2} x^{2} + d^{2}} \]
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Timed out. \[ \int \frac {\left (d^2-e^2 x^2\right )^{7/2}}{d+e x} \, dx=\int \frac {{\left (d^2-e^2\,x^2\right )}^{7/2}}{d+e\,x} \,d x \]
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